Answer :
[tex]\left\{\begin{array}{ccc}y=\frac{1}{2}x+5\\y=-\frac{3}{2}x-7\end{array}\right\\\\subtitute:\\\\\frac{1}{2}x+5=-\frac{3}{2}x-7\ \ \ \ |subtract\ 5\ from\ both\ sides\\\\\frac{1}{2}x=-\frac{3}{2}x-12\ \ \ \ |add\ \frac{3}{2}x\ to\ both\ sides\\\\\frac{4}{2}x=-12\\\\2x=-12\ \ \ \ |divide\ both\ sides\ by\ 2\\\boxed{x=-6}\\\\subtitute\ value\ of\ "x"\ to\ first\ equation:\\\\y=\frac{1}{2}\cdot(-6)+5=-3+5=\boxed2\\\\Answer:\boxed{\boxed{x=-6\ and\ y=2}}[/tex]
