Answer :
5 gram of 197 Au contain 1.53*10^22 atoms. so just multiply that with 59 to get 295 grams :)
The molar mass of gold, Au, as seen on the periodic table, is 196.97 grams per mole. So, do this to find the number of moles in a 295 gram sample:
[tex](295g\ Au)(\frac{1mol\ Au}{196.97g\ Au}) = 1.49769mol\ Au[/tex]
So, a 295 gram sample of gold has about 1.5 moles of gold in it.
To find the number of atoms, multiply the number of moles by Avogadro's number:
[tex](1.49769mol\ Au)(\frac{6.022*10^{23}\ atoms}{mol}) = 9.02 * 10^{23}\ atoms\ Au[/tex]
[tex](295g\ Au)(\frac{1mol\ Au}{196.97g\ Au}) = 1.49769mol\ Au[/tex]
So, a 295 gram sample of gold has about 1.5 moles of gold in it.
To find the number of atoms, multiply the number of moles by Avogadro's number:
[tex](1.49769mol\ Au)(\frac{6.022*10^{23}\ atoms}{mol}) = 9.02 * 10^{23}\ atoms\ Au[/tex]
