A tank of water holding 528 kl of water begain to empty at a rate of 10 kl/min at the same time a another tank whitch is empty begins to fill at a rate of 14kl/min let k repreasens the number of kiloliters of water and let t repreasent time in min the system models the solution
How long will it take for each tank to have the Same amount of water , and how much water will that be
It will take __minitutes for both tanks to hold equal amounts of water . They will each hold ___ kiloliters.
This is a system of equations. The first equation represents the tank being emptied and the second equation represents the tank being filled:
k = -10t + 528 k = 14t
To solve this system of equations, we will use substitution. The second equation says that k is equal to 14t, so we can substitute 14t for k in the first equation.
14t = -10t + 528 24t = 528 t = 22
Now that we have t, we can use it to find k by plugging it in to the second equation:
k = 14(22) k = 308
So, it will take 22 minutes for both tanks to hold equal amounts of water. They will each hold 308 kiloliters.
