Answer :
a) 125 * 10 = 1250 chinchillas in a year;
1250 * 2 = 2500 chinchillas in two years;
b) y = x + 433, where 433 = 933 - 500;
c) 933 + 433 = 1366 chinchillas they have at the end of two years;
1250 * 2 = 2500 chinchillas in two years;
b) y = x + 433, where 433 = 933 - 500;
c) 933 + 433 = 1366 chinchillas they have at the end of two years;