Answer :

[tex]f(1)=16\\ f(n)=f(n-1)+12\\\\ f(2)=f(2-1)+12=f(1)+12=16+12=28\\ f(3)=f(3-1)+12=f(2)+12=28+12=40\\ f(4)=f(4-1)+12=f(3)+12=40+12=52\\\\ \boxed{f(4)=52} [/tex]

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