Answer :

naǫ
[tex]\frac{6x-1}{5}=\frac{3}{1} \ \ \ |\hbox{cross multiply} \\ 6x-1=3 \times 5 \\ 6x-1=15 \\ 6x=15+1 \\ 6x=16 \\ x=\frac{16}{6} \\ x=\frac{8}{3} \\ x=2\frac{2}{3}[/tex]
thisisbenmanley
In order to solve for x, you need to isolate the x on one side.  First, you need to multiply the 5 onto the other side to get rid of the fraction.  Then, just add 1 and divide by 6 to isolate the x (steps will be shown below):

[tex]\frac{6x-1}{5}=\frac{3}{1}\\5(\frac{6x-1}{5})=5(3)\\6x-1=15\\6x-1+1=15+1\\6x=16\\6x/6=16/6\\x=\frac{16}{6}=\frac{8}{3}[/tex]

So, x = 8/3

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