Answer :
Convert the equation to the slope-intercept form:
[tex]2x+2y=5 \\ 2y=-2x+5 \ \ \ |\div 2 \\ y=-x+\frac{5}{2} \\ \\ y=mx+b, \ m - \hbox{the slope} \\ y=-x+\frac{5}{2} \\ \boxed{m=-1} - \hbox{the slope}[/tex]
TRUE
[tex]2x+2y=5 \\ 2y=-2x+5 \ \ \ |\div 2 \\ y=-x+\frac{5}{2} \\ \\ y=mx+b, \ m - \hbox{the slope} \\ y=-x+\frac{5}{2} \\ \boxed{m=-1} - \hbox{the slope}[/tex]
TRUE
