Answer :
The Molecular Mass for Phosphorus is 31 grames / mole.
So, 31g. P.....................1 mole
2.3g. P ..........................x mole
[tex]x= \frac{2,3}{31} = \boxed {0,07} \hbox { moles }[/tex]
So, 31g. P.....................1 mole
2.3g. P ..........................x mole
[tex]x= \frac{2,3}{31} = \boxed {0,07} \hbox { moles }[/tex]
1.Molar mass of phos.=30.97g/mol
2.n=m/M
=2.3g/30.97g/mol
=0.07mol
3. therefore the amount of moles in 2.3g of phosphorus is 0.07mol
2.n=m/M
=2.3g/30.97g/mol
=0.07mol
3. therefore the amount of moles in 2.3g of phosphorus is 0.07mol
