Answer :
[tex]-2x+4y+6=0 \\
x-5y+3=0 \\ \\
\hbox{solve the 1st equation for x:} \\
-2x+4y+6=0 \ \ \ |-(4y+6) \\
-2x=-4y-6 \ \ \ |\div (-2) \\
x=2y+3 \\ \\
\hbox{substitute 2y+3 for x in the 2nd equation:} \\
2y+3-5y+3=0 \\
-3y+6=0 \ \ \ |-6 \\
-3y=-6 \ \ \ |\div (-3) \\
y=2 \\ \\
x-5y+3=0 \\
x-5 \times 2+3=0 \\
x-10+3=0 \\
x-7=0 \ \ \ |+7 \\
x=7 \\ \\
(x,y)=(7,2)[/tex]
