princess614
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a rectangle is 4 times as long as it wide. if the length is increased by 4 inches and the width is decreased by 1 inch, the area will be 60 square inches. what were the dimensions of the original rectangle. and please help me



Answer :

luana
[tex]x-\ width\\ y-\ length\\ 4x=y\\ (y+4)(x-1)=60\\ (4x+4)(x-1)=60\\ 4x^2-4x+4x+4=60\ \ | subtract\ 4\\ 4x^2=56\ \ | divide\ by\ 4\\ x^2=14\\ x=\sqrt{14}\\ y=4\sqrt{14}\\\\ Dimensions:\ width=\sqrt{14}in,\ length=4\sqrt{14}in.[/tex]

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