Answer :

naǫ
[tex](\sqrt{7})^{6x}=49^{x-6} \\ (7^\frac{1}{2})^{6x}=(7^2)^{x-6} \\ 7^{\frac{1}{2} \times 6x}=7^{2(x-6)} \\ 7^{3x}=7^{2x-12} \\ 3x=2x-12 \\ 3x-2x=-12 \\ x=-12[/tex]

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