Answer :
[tex]-2x^2+6x-3=0 \\ \\
a=-2 \\ b=6 \\ c=-3 \\ \Delta=b^2-4ac=6^2-4 \times (-2) \times (-3)=36-24=12[/tex]
The value of the discriminant is 12.
Since the discriminant is greater than zero, the equation has two real solutions.
The value of the discriminant is 12.
Since the discriminant is greater than zero, the equation has two real solutions.
