Answer :
The answer is 14 :
To find out the greatest sum of a number's possible factors you must choose those which are furthest from each other, in this case : [tex]6=6\cdot 1[/tex] 6 and 1 are the furthest. The length of long side of the rectangle is : 6 and the short side is 1. Lets calculate its perimeter : [tex]2(6+1)\\ 2\cdot 7=14[/tex]
The greatest possible perimeter is 14
To find out the greatest sum of a number's possible factors you must choose those which are furthest from each other, in this case : [tex]6=6\cdot 1[/tex] 6 and 1 are the furthest. The length of long side of the rectangle is : 6 and the short side is 1. Lets calculate its perimeter : [tex]2(6+1)\\ 2\cdot 7=14[/tex]
The greatest possible perimeter is 14
Answer:
14 cm
Explanation:
We know that the area of the rectangle is calculated as:
area = length * width
We also know that the area is 6 cm²
This means that multiplying the length and width would give us 6
6 can be obtained as follows:
6 = 1 * 6 = 2 * 3
Let's check each:
If the length and width were 1 and 6:
perimeter = 2(length + width)
perimeter = 2(1+6)
perimeter = 2 * 7
perimeter = 14 cm
If the length and width were 1 and 3:
perimeter = 2(length + width)
perimeter = 2(2+3)
perimeter = 2 * 5
perimeter = 10 cm
By comparing, we can note that:
the largest possible perimeter is 14 cm
Hope this helps :)
14 cm
Explanation:
We know that the area of the rectangle is calculated as:
area = length * width
We also know that the area is 6 cm²
This means that multiplying the length and width would give us 6
6 can be obtained as follows:
6 = 1 * 6 = 2 * 3
Let's check each:
If the length and width were 1 and 6:
perimeter = 2(length + width)
perimeter = 2(1+6)
perimeter = 2 * 7
perimeter = 14 cm
If the length and width were 1 and 3:
perimeter = 2(length + width)
perimeter = 2(2+3)
perimeter = 2 * 5
perimeter = 10 cm
By comparing, we can note that:
the largest possible perimeter is 14 cm
Hope this helps :)
