Answer :

The original number is divisible by 9 if and only if the sum of it's digits
is divisible by 9.

[tex]A.\\288\to2+8+8=18\ is\ divisible\ by\ 9\ \boxed{ANSWER}\\\\B.\\377\to3+7+7=17\ isn't\ divisible\ by\ 9\ \boxed{NO}\\\\C.\\466\to4+6+6=16\ isn't\ divisible\ by\ 9\ \boxed{NO}\\\\D.\\555\to5+5+5=15\ isn't\ divisible\ b\y\ 9\ \boxed{NO}[/tex]

Other Questions