Answer :

[tex]-2\leq\dfrac{3}{5}z+\dfrac{4}{5}<6 \\ -10\leq3z+4<30\\ -14\leq3z<26\\ -\dfrac{14}{3}\leq z<\dfrac{26}{3}\\ z\in\left[-\dfrac{14}{3},\dfrac{26}{3}\right)[/tex]

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