Answer :
[tex]2x+3y=-12 \\
\underline{-2x+y=4 \ \ \ } \\
3y+y=-12+4 \\
4y=-8 \\
y=-2 \\ \\
2x+3y=-12 \\
2x+3 \times (-2)=-12 \\
2x-6=-12 \\
2x=-12+6 \\
2x=-6 \\
x=-3 \\ \\
\boxed{(x,y)=(-3,-2)}[/tex]
2x + 3y = -12
-2x + y = 4
First, you have to pick a variable to cancel out (eliminate)
the 'y' would be the easiest
Multiply the bottom equation by a -3
2x + 3y = -12
6x - 3y = -12
Then, you practically add them together (the y's will cancel out)
8x = -24
Divide both sides by 8
x = -3
Then, plug your x into either equation
-2 (-3) + y = 4
6 + y = 4
Subtract your 6 over to the 4
y = -2
(You can check this buy plugging in both your x and y into both equations)
(x, y)
(-3, -2)
-2x + y = 4
First, you have to pick a variable to cancel out (eliminate)
the 'y' would be the easiest
Multiply the bottom equation by a -3
2x + 3y = -12
6x - 3y = -12
Then, you practically add them together (the y's will cancel out)
8x = -24
Divide both sides by 8
x = -3
Then, plug your x into either equation
-2 (-3) + y = 4
6 + y = 4
Subtract your 6 over to the 4
y = -2
(You can check this buy plugging in both your x and y into both equations)
(x, y)
(-3, -2)
