Propane and oxygen react according to the equation: C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(g).
How many grams of water can be produced from the complete combustion of 2.0 moles of C₃H₈(g)?
a. 144.0
b. 82.0
c. 8.0
d. 44.8
e. 22.4



Answer :

1mole of propane produced 4 moles of water
44g of propane produced 18×4=72g of water
2moles of propane=2×44=88
44:72
88:x
44x=88×72
x=2×72
x=144.0grams option (a)

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