Answer :
( x - 5) / ( -6 - 5) = (y - 4)/( 3 - 4) <=> (x-5)/(-11) = (y-4)/(-1) <=> x - 5 = 11y - 44 <=>
x - 11y + 39 = 0;
x - 11y + 39 = 0;
First you have to find the slope of the line.
(y2 -y1) / (x2 - x1) = slope
so (3 - 4) / ( -6 - 5) = -1/ -11 so the slope of the line is 1/11
Now you write y = mx + b then substitute in one of the points with x and y
4 = (1/11)(5) + b
4 = 5/11 + b
-5/11= - 5/11 change the 4 into 44/ 11 and subtract
44 / 11 - 5/11= b
39/11 = b now it depends on your teacher and text
usually, you can substitute the fraction for your b
y = mx + b
y = 1/11 x + 39/11 so this is your answer
Does that make sense or did I make a mathematical error?
(y2 -y1) / (x2 - x1) = slope
so (3 - 4) / ( -6 - 5) = -1/ -11 so the slope of the line is 1/11
Now you write y = mx + b then substitute in one of the points with x and y
4 = (1/11)(5) + b
4 = 5/11 + b
-5/11= - 5/11 change the 4 into 44/ 11 and subtract
44 / 11 - 5/11= b
39/11 = b now it depends on your teacher and text
usually, you can substitute the fraction for your b
y = mx + b
y = 1/11 x + 39/11 so this is your answer
Does that make sense or did I make a mathematical error?
