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Josiah and his friends are going to the movies. Each ticket costs $10, and popcorn is $5 a bag. There is a $3 service fee for the entire purchase. He has $75. If he buys 4 tickets, how many bags of popcorn can he buy? if x=number of tickets and y=number of popcorn which of the following inequalities would you use to answer the problem?

A x+y=75
B 10x+5y+3≤75
C 10x+5y≤75
D 10x+5y+3≥75



Answer :

B
Because if x equals the number of tickets the it would be 10 X x. Same with the popcorn. for example: x=5 And y =3. it would be
10(5)+5(3)+3=$68
pemanuel

Answer:

B.

Step-by-step explanation:

If each ticket costs $10 and each popcorn costs $5, with x = number of tickets and y = number of popcorn and $3 the service we have

10x+5y+3 = total cost.

Now, he has a total of $75 and he buys 4 tickets so

10(4)+5y+3 = 75

40+5y+3 = 75

43+5y=75

5y = 75-43

5y = 32

y = 32/5 = 6.4 ≈ 6 popcorn.

Then, he can buy 6 popcorns. Now, to find the inequality we need to know that if he has $75, the total cost can't exceed $75, that is, the total cost needs to be less or equal to $75.

10x+5y+3 ≤75.

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