Answer :
[tex]3 \ KOH + FeCl_3 \to Fe(OH)_3 + 3 \ KCl[/tex]
3 moles of KOH - 1 mole of Fe(OH)₃
0.385 moles of KOH - x moles of Fe(OH)₃
cross multiply:
[tex]3x=1 \times 0.385 \\ 3x=0.385 \ \ \ |\div 3 \\ x \approx 0.128[/tex]
0.128 moles of iron(III) hydroxide are formed.
3 moles of KOH - 1 mole of Fe(OH)₃
0.385 moles of KOH - x moles of Fe(OH)₃
cross multiply:
[tex]3x=1 \times 0.385 \\ 3x=0.385 \ \ \ |\div 3 \\ x \approx 0.128[/tex]
0.128 moles of iron(III) hydroxide are formed.
