Answer :
Twice a number plus twice a second number is 310.
[tex]2x + 2y = 310[/tex]
The difference between the numbers is 55.
[tex]x-y = 55[/tex]
Divide the first equation by 2 to get a 3rd equation:
[tex]x+y=155[/tex]
Add the second and third equations together:
[tex]x-y=55[/tex]
[tex]x+y=155[/tex]
[tex]2x=210[/tex]
[tex]x=105[/tex]
Put x=105 into the second equation to get:
[tex]105-y=55[/tex]
[tex]y=50[/tex]
So you're answers are x=105 and y=50.
[tex]2x + 2y = 310[/tex]
The difference between the numbers is 55.
[tex]x-y = 55[/tex]
Divide the first equation by 2 to get a 3rd equation:
[tex]x+y=155[/tex]
Add the second and third equations together:
[tex]x-y=55[/tex]
[tex]x+y=155[/tex]
[tex]2x=210[/tex]
[tex]x=105[/tex]
Put x=105 into the second equation to get:
[tex]105-y=55[/tex]
[tex]y=50[/tex]
So you're answers are x=105 and y=50.
The numbers by writing and solving a system of equations are 50 and 105
System of equations
Let the unknown numbers be x and y
If twice a number plus twice a second number is 310, then;
2x + 2y = 310
x + y = 155
x = 155 - y
Also, If the difference of the numbers is 55, hence;
x - y = 55
155 - y - y = 55
155 - 2y = 55
-2y = 55 - 505
2y = 100
y = 50
Substitute y = 25 into 1 to have:
x = 155 - 50
x = 105
Hence the numbers by writing and solving a system of equations are 50 and 105
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