Answer :
[tex]a_n=n(n-1)-5 \\ \\
a_1=1(1-1)-5=1 \times 0-5=0-5=-5 \\
a_2=2(2-1)-5=2 \times 1-5=2-5=-3 \\
a_3=3(3-1)-5=3 \times 2-5=6-5=1 \\
a_4=4(4-1)-5=4 \times 3-5=12-5=7[/tex]
The first four terms are -5, -3, 1 and 7.
The first four terms are -5, -3, 1 and 7.
