MarthaMwamba5
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a group of backpackers hiked 38 km over three days. the first day, they hiked 1 km less than 3 times as far as the second day. the third day, they hiked 2 km less than the first day. how far did they hike the first day



Answer :

specter
38 km= (3x-1)+x+((3x-1)-2)
38 = 3x-1+x+3x-1-2
38 = 7x-4
7x=42
x=6 km --> second day
Test: 38 = (3*6-1)+6(3*6-1)-2)
--> frist day: 3*6-1 = 17 km

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