Answer :
My trig is a bit rusty, but I'll give it a try:
[tex]$h=4-3\cos((t+5)\frac{\pi }{6})$[/tex]
Here, h represents the height and t represents the time (as in 1:00, 2:00, etc.). The curve works, but it was after a bit of trial and error.
[tex]$h=4-3\cos((t+5)\frac{\pi }{6})$[/tex]
Here, h represents the height and t represents the time (as in 1:00, 2:00, etc.). The curve works, but it was after a bit of trial and error.