Answer :
[tex]v=v(0)+at[/tex]
[tex]9.20=0+(9.81*t)[/tex] [tex]| [/tex]9.81 because the fall is due to gravity.
[tex]t= \frac{9.20}{9.81} [/tex]
[tex]t=0.94seconds[/tex]
[tex]9.20=0+(9.81*t)[/tex] [tex]| [/tex]9.81 because the fall is due to gravity.
[tex]t= \frac{9.20}{9.81} [/tex]
[tex]t=0.94seconds[/tex]
Answer:
1.87 s
Explanation:
Initial speed of throw = 9.20 m/s
Net vertical displacement = 0
The bowling pin would be in free fall i.e. a = 9.8 m/s²
Use the second equation of motion:
s = ut + 0.5at²
0 = (9.20)t-0.5(9.8)(t²)
9.20 = 4.9 t
⇒t = 1.87 s
Thus, the total time of flight, the time elapses before the bowling pin falls in juggler's hand is 1.87 s.
