Answer :

ayec
(x+1)(x+3)

x^2+3x+x+3

x^2+4x+3

That's how you expand it.

and to get the answer, you can equal (x+1)(x+3) to 0.

(x+1)(x+3)=0

x+1=0 or x+3=0

x=-1 or x=-3
konrad509
[tex](x+1)(x+3) =x^2+3x+x+3=x^2+4x+3[/tex]

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