Answer :
Well, you transform the standard form equation into slope-intercept form (y=mx+b), since you can only graph it using this form.
First of all, the layout of the equation is [tex]Ax+By=C[/tex]
So, in this case, A is 2, B is 5, and C is 25.
Now, to put it into slope intercept form, you either use the formula to change it and solve it:
[tex]y= \frac{-A}{B}x+ \frac{C}{B} \\ y= \frac{-2}{-5}x+ \frac{25}{-5} \\ \\ y= \frac{2}{5}x-5 [/tex]
Or you can just solve for y:
[tex]2x-5y=25 \\ 2x-5y-2x=25-2x \\ -5y=-2x+25 \\ \frac{-5y}{-5}= \frac{-2x+25}{-5} \\ \\ y= \frac{2}{5}x-5 [/tex]
In addition, I attached what the graph looks like.
Hope this helps!
First of all, the layout of the equation is [tex]Ax+By=C[/tex]
So, in this case, A is 2, B is 5, and C is 25.
Now, to put it into slope intercept form, you either use the formula to change it and solve it:
[tex]y= \frac{-A}{B}x+ \frac{C}{B} \\ y= \frac{-2}{-5}x+ \frac{25}{-5} \\ \\ y= \frac{2}{5}x-5 [/tex]
Or you can just solve for y:
[tex]2x-5y=25 \\ 2x-5y-2x=25-2x \\ -5y=-2x+25 \\ \frac{-5y}{-5}= \frac{-2x+25}{-5} \\ \\ y= \frac{2}{5}x-5 [/tex]
In addition, I attached what the graph looks like.
Hope this helps!
