Answer :
For this case we have the following expression:
[tex] \frac{1}{3} + \frac{1}{3} [/tex]
We observe that the numerator in both fractions is smaller than the denominator.
Therefore, we are in the presence of two proper fractions.
Since the denominator of both fractions is equal, then the result is given by:
[tex] \frac{1}{3} + \frac{1}{3} = \frac{2}{3} [/tex]
The numerators are added and the denominator is the same.
The result is also a proper fraction because the numerator is smaller than the denominator.
[tex] \frac{1}{3} + \frac{1}{3} [/tex]
We observe that the numerator in both fractions is smaller than the denominator.
Therefore, we are in the presence of two proper fractions.
Since the denominator of both fractions is equal, then the result is given by:
[tex] \frac{1}{3} + \frac{1}{3} = \frac{2}{3} [/tex]
The numerators are added and the denominator is the same.
The result is also a proper fraction because the numerator is smaller than the denominator.
Answer:
Both fractions in the expression [tex]\frac{1}{3}+\frac{1}{3}[/tex] are examples of proper fractions.
Step-by-step explanation:
Given : Both fractions in the expression [tex]\frac{1}{3}+\frac{1}{3}[/tex]
To find : That both the fractions is the example of?
Solution :
In the fraction [tex]\frac{1}{3}[/tex] numerator is smaller than the denominator.
Therefore, The fraction is proper fraction.
When we add the fractions,
The denominator of both fractions is equal,
[tex]\frac{1}{3}+\frac{1}{3}=\frac{2}{3}[/tex]
In this fraction also the numerator is smaller than the denominator
Therefore, The fraction is proper fraction.
Hence, Both fractions in the expression [tex]\frac{1}{3}+\frac{1}{3}[/tex] are examples of proper fractions.
