Answer :
[tex]x^2+9x+14=0\\\\ x_{1}=\frac{-b-\sqrt{b^2-4ac} }{2a}=\frac{-9-\sqrt{9^2-4*1*14 } }{2 }=\frac{-9-\sqrt{81-56 } }{2 }= \frac{-9-\sqrt{25 } }{2 }=\\\\=\frac{-9-5 }{2 }=\frac{-14 }{2 }= -7\\\\ x_{2}=\frac{-b+\sqrt{b^2-4ac} }{2a}=\frac{-9+\sqrt{9^2-4*1*14 } }{2 }= \frac{-9+5 }{2 }=\frac{- 4 }{2 }= -2[/tex]
