Answer :
(((1/y - 1) + (5/12)) = (-2/3y - 3))
((((1)(12)/12(y - 1) + (5(y + 1)/12(y + 1) = (-2/3y - 3))
((12/12y - 12) + (5y + 5/12y - 12)) = (-2/3y - 3))
((5y + 17/12y - 12) = (-2/3y - 3)
(12y - 12/5 + 17) × (5y + 17/12y - 12) = (-2/3y - 3)(12y - 2/5 + 17)
y = -21y + 4/66y - 66
y = -7/22 - 2/33
y = -25/66
((((1)(12)/12(y - 1) + (5(y + 1)/12(y + 1) = (-2/3y - 3))
((12/12y - 12) + (5y + 5/12y - 12)) = (-2/3y - 3))
((5y + 17/12y - 12) = (-2/3y - 3)
(12y - 12/5 + 17) × (5y + 17/12y - 12) = (-2/3y - 3)(12y - 2/5 + 17)
y = -21y + 4/66y - 66
y = -7/22 - 2/33
y = -25/66
