Answer :

[tex]x^2+5x=3x+11\\ x^2+2x-11=0\\ x^2+2x+1-12=0\\ (x+1)^2=12\\ x+1=\sqrt{12} \vee x+1=-\sqrt{12}\\ x=-1+2\sqrt3 \vee x=-1-2\sqrt3[/tex]

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