Answer :
so 9x^2+12x+4=0
so the quadratic formulat is (-b+/-(squrt(b^2-4ac)))/(2a)=x
subsitute
ax^2+bx+c=
9=a
12=b
4=c
(-12+/-(squrt(12^2-4(9)(4))))/(2(9))=x
(-12+/-(squrt(144^2-144)))/18)=x
(-12+/-0)/18)=x
-12/18=x
-2/3=x
so the quadratic formulat is (-b+/-(squrt(b^2-4ac)))/(2a)=x
subsitute
ax^2+bx+c=
9=a
12=b
4=c
(-12+/-(squrt(12^2-4(9)(4))))/(2(9))=x
(-12+/-(squrt(144^2-144)))/18)=x
(-12+/-0)/18)=x
-12/18=x
-2/3=x
[tex] Discriminant= b^{2}-4.a.c \\ \\ We\:need\:to:-b+ \sqrt{discriminant} /2a \\ \\ 9x^{2} +12x+4=0 \\ => 12^{2} -4.9.4 \\ 144-144=0 \\ \sqrt{0} =0 \\ \\ -12+ 0/18= \frac{-12}{18} = \frac{-2}{3} \\ \\ That`s\: enough=>x= \frac{-2}{3} \\ \\ \framebox[1.1\width]{Good Luck!} \par[/tex]
