Answer :
[tex]4x^3+7x^2-5x=6\\
4x^3+7x^2-5x-6=0\\
4x^3+8x^2-x^2-2x-3x-6=0\\
4x^2(x+2)-x(x+2)-3(x+2)=0\\
(4x^2-x-3)(x+2)=0\\
(4x^2-4x+3x-3)(x+2)=0\\
(4x(x-1)+3(x-1))(x+2)=0\\
(4x+3)(x-1)(x+2)=0\\
x=-\dfrac{3}{4} \vee x=1 \vee x=-2[/tex]
