Answer :
Line 1
[tex]m=\dfrac{7-6}{-2-0}=-\dfrac{1}{2}[/tex]
Line 2
[tex]m=\dfrac{0-(-3)}{3-0}=\dfrac{3}{3}=1[/tex]
Both lines have different slopes which means they're certainly not parallel and therefore they have one intersection point. So there is one solution.
[tex]m=\dfrac{7-6}{-2-0}=-\dfrac{1}{2}[/tex]
Line 2
[tex]m=\dfrac{0-(-3)}{3-0}=\dfrac{3}{3}=1[/tex]
Both lines have different slopes which means they're certainly not parallel and therefore they have one intersection point. So there is one solution.
