Answer :
[tex]7x + 5y = 29|\cdot5\\
21x - 25y = -33\\\\
35x+25y=145\\
\underline{21x-25y=-33}\\
56x=112\\
x=2\\\\
7\cdot2+5y=29\\
14+5y=29\\
5y=15\\
y=3\\\\
\boxed{(x,y)=(2,3)}
[/tex]
5*(7x + 5y = 29)
+ 21x - 25y = -33
35x + 25y = 145
+ 21x - 25y = -33
56 x + 0y = 112
56x = 112
x = 2
Plug the x back in to the original equation to solve for y.
7x + 5y = 29
7(2) + 5y = 29
14 + 5y = 29
5y = 15
y = 3
21x - 25y = -33
21(2) - 25y = -33
42 - 25y = -33
-25y = -75
y = 3
x = 2 and y = 3
+ 21x - 25y = -33
35x + 25y = 145
+ 21x - 25y = -33
56 x + 0y = 112
56x = 112
x = 2
Plug the x back in to the original equation to solve for y.
7x + 5y = 29
7(2) + 5y = 29
14 + 5y = 29
5y = 15
y = 3
21x - 25y = -33
21(2) - 25y = -33
42 - 25y = -33
-25y = -75
y = 3
x = 2 and y = 3
