A 34.87 g sample of a substance is initially at 27.1 C. after absorbing 1071 J of heat, the temperature of the substance is 145.0 C. what is the specific heat (SH) of the substance?

SH=___ J / g * C

Question

15-03-2015
Chemistry

Answered

A 34.87 g sample of a substance is initially at 27.1 C. after absorbing 1071 J of heat, the temperature of the substance is 145.0 C. what is the specific heat (SH) of the substance?

SH=___ J / g * C

Answer :

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Since3122015 Since3122015 · Answer 1 · 2015-03-15T14:26:23-04:00

Since3122015 Since3122015

15-03-2015

[tex]H= \frac{1071}{34.87}*145\\H= \frac{155295}{34.87} \\H= \frac{15529500}{3487} \\H=4453.542[/tex]

Answer Link

nicomtorres nicomtorres · Answer 2 · 2021-01-29T11:33:07-05:00

nicomtorres nicomtorres

29-01-2021

Answer: .1044 J/g*C°

Explanation: The equation you need to use for this problem is :

c= q/m* ΔT

We are given

T1= 27.1 C°

T2= 145 C°

M= 34.87g

1071 J absorbed heatt

So let's solve specific heat

c= 1071J/ (87grams)*(145 C°- 27.1 C°)

c= 1071J/10,257.3 g*C°

c= .1044 J/g*C°

c=specific heat

Answer Link

A 34.87 g sample of a substance is initially at 27.1 C. after absorbing 1071 J of heat, the temperature of the substance is 145.0 C. what is the specific heat (SH) of the substance? SH=___ J / g * C

Answer :

Other Questions

A 34.87 g sample of a substance is initially at 27.1 C. after absorbing 1071 J of heat, the temperature of the substance is 145.0 C. what is the specific heat (SH) of the substance?

SH=___ J / g * C