Answer :

[tex]135|3\\.\ 45| 3\\.\ 15|3\\.\ \ 5|5\\.\ \ 1|\\135=\fbox3\cdot\fbox3\cdot\fbox3\cdot5\\\\81|3\\27|3\\.\ 9|3\\.\ 3|3\\.\ 1|\\81=\fbox3\cdot\fbox3\cdot\fbox3\cdot3\\\\the\ highest\ common\ factor\ of\ 135\ and\ 81\\\\=\fbox3\cdot\fbox3\cdot\fbox3=\boxed{\boxed{27}}[/tex]

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