Answer :
assume log base 9
log(x+6) - log(x) - log(2) = 0
log((x+6)/(2x)) = 0
(x+6)/(2x) = 1
x+6 = 2x
x = 6
log(x+6) - log(x) - log(2) = 0
log((x+6)/(2x)) = 0
(x+6)/(2x) = 1
x+6 = 2x
x = 6
