Answer :
Let's say he's gonna use x grams of 90% gold alloy and y grams of 50% gold alloy.
The total percentage of gold in the mixture will thus be (x*0.9+y*0.5)/8=0.75 (=75%)
What is more x+y=8
The system is thus x+y=8, 0.9x+0.5y=8*0.75=6
From the first one we get y=8-x, which we insert in the second one : x(0.9-0.5)+0.5*8=4 hence x=(6-0.5*8)/(0.4)=5 and y=8-5=3
The answer is 5 grams of 90% gold and 3 grams of 50% gold
The total percentage of gold in the mixture will thus be (x*0.9+y*0.5)/8=0.75 (=75%)
What is more x+y=8
The system is thus x+y=8, 0.9x+0.5y=8*0.75=6
From the first one we get y=8-x, which we insert in the second one : x(0.9-0.5)+0.5*8=4 hence x=(6-0.5*8)/(0.4)=5 and y=8-5=3
The answer is 5 grams of 90% gold and 3 grams of 50% gold