Answer :
No. of ounces Kim ate = 3/8 * 16 = 6 ounces
No. of ounces Courtney ate = 1/4 * 16 = 4 ounces
No. of ounces left = Total amt. of cereals - Kim's share - Courtney's share
= 16 - 6 - 4 =6 ounces
Fraction of left over cereal = 6/16 = 3/8
No. of ounces Courtney ate = 1/4 * 16 = 4 ounces
No. of ounces left = Total amt. of cereals - Kim's share - Courtney's share
= 16 - 6 - 4 =6 ounces
Fraction of left over cereal = 6/16 = 3/8
³/₈
Further explanation
We will solve the problem of subtraction between fractions.
Given:
Kim and Courtney share a 16-ounce of the box of cereal.
By the end of the week:
- Kim has eaten ³/₈ of the box, and
- Courtney has eaten ¹/₄ of the box of cereal.
Question:
What fraction of the box is left?
The Process:
Kim has eaten ³/₈ of the box of cereal. Let's calculate how many fractions of the box are left after Kim has eaten them.
[tex]\boxed{ \ 1 - \frac{3}{8} = \ ? \ }[/tex]
[tex]\boxed{ \ \frac{8}{8} - \frac{3}{8} = \frac{5}{8} \ }[/tex]
Hence, the rest of the box after Kim has eaten ³/₈ of the box is
[tex]\boxed{\boxed{ \ \frac{5}{8} \ }}[/tex]
Furthermore, Courtney has eaten ¹/₄ of the box of cereal. Let's calculate how many fractions of the box are left again after Courtney ate the remaining part since Kim had eaten it before.
[tex]\boxed{ \ \frac{5}{8} - \frac{1}{4} = \ ? \ }[/tex]
Before we subtract, the denominator must be equated. Prepare ¹/₄ to be ²/₈. The numerator and denominator are multiplied by two.
[tex]\boxed{ \ \frac{5}{8} - \frac{2}{8} = \frac{3}{8} \ }[/tex]
Thus, the fraction of the box left after Kim and Courtney have eaten is [tex]\boxed{\boxed{ \ \frac{3}{8} \ }}.[/tex] [tex]\boxed{ \ The \ Answer \ }[/tex]
- - - - - - - - - -
Quick Steps:
[tex]\boxed{ \ 1 - \frac{3}{8} - \frac{1}{4} = \ ? \ }[/tex]
[tex]\boxed{ \ \frac{8}{8} - \frac{3}{8} - \frac{2}{8} = \boxed{ \ \frac{3}{8} \ } \ }[/tex]
The summary scheme is as follows:
Initial conditions
[tex]\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot} \rightarrow \boxed{ \ one \ part = \frac{8}{8} \ }[/tex]
Kim has eaten ³/₈ of the box: [tex]\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}[/tex] [tex]\rightarrow \boxed{ \ \frac{3}{8} \ }[/tex]
Courtney has eaten ¹/₄ (or ²/₈) of the box: [tex]\boxed{\cdot}\boxed{\cdot}[/tex] [tex]\rightarrow \boxed{ \ \frac{2}{8} \ }[/tex]
Final conditions
[tex]\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}[/tex] is subtracted by [tex]\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}[/tex] and is subtracted by [tex]\boxed{\cdot}\boxed{\cdot}[/tex] equal [tex]\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}[/tex] as the remaining part [tex]\rightarrow \boxed{\boxed{ \ \frac{3}{8} \ }}[/tex]
Learn more
- The sum of ¹/₆, ²/₃, and ¹/₄ https://brainly.com/question/3298276#
- ²/₇m - ¹/₇ = ³/₁₄ solve step by step https://brainly.com/question/4853649
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Keywords: Kim and Courtney, share, a 16-ounce of the box of cereal, ³/₈ of the box, ¹/₄, what fraction of the box is left, ³/₈, subtraction, the denominator, the numerator
