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the area of rectangular lot is represented by 6t^2+13t-5. what are the dimensions of the rectangular lot?



Answer :

[tex]6t^2+13t-5=\\ 6t^2-2t+15t-5=\\ 2t(3t-1)+5(3t-1)=\\ (2t+5)(3t-1)[/tex]

The dimensions are [tex]2t+5[/tex] and [tex]3t-1[/tex]

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