Answer :
The produced grams of [tex]H_2O[/tex] is [tex]36 \ g[/tex].
In the metric system, a gram is defined as one thousandth [tex](1 \times 10^{-3})[/tex] of a kilogram.
How do determine the number of moles?
[tex]\mathrm{Number \ of \ moles} = \frac{\mathrm{Mass}}{ \mathrm{Molar \ mass}}[/tex]
[tex]$\mathrm{NaOH}+\mathrm{HCl} \longrightarrow \mathrm{NaCl}+\mathrm{H}_{2} \mathrm{O}$[/tex]
1 mol of [tex]$\mathrm{NaOH}$[/tex] reacts with 1 mol of [tex]$\mathrm{HCl}$[/tex] and produces [tex]$1 \mathrm{~mol}$[/tex]of [tex]$\mathrm{NaCl}$[/tex] and 1 mol of [tex]$\mathrm{H}_{2} \mathrm{O}$[/tex] Number of moles of [tex]$\mathrm{NaCl}$[/tex]
[tex]$\begin{aligned}&=\frac{\text { mass }}{\text { molar mass }} \\&=\frac{116 \mathrm{~g}}{58.44 \mathrm{~g} / \mathrm{mol}} \\&=1.98 \mathrm{~mol}\end{aligned}$[/tex]
Number of moles produced [tex]$\mathrm{H}_{2} \mathrm{O}=1.98 \mathrm{~mol}$[/tex]
Amount of produced [tex]$\mathrm{H}_{2} \mathrm{O}$[/tex]
[tex]\mathrm{= mole \ number $\times$ molar mass}[/tex]
[tex]$=1.98 \mathrm{~mol} \times 18 \mathrm{~g} / \mathrm{mol}$$[/tex]
[tex]\begin{aligned}&=35.64 \mathrm{~g} \\&=36 \mathrm{~g}\end{aligned}$[/tex]
Therefore, produced grams of [tex]H_2O[/tex] is [tex]36 \ g[/tex].
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