Answer :
the axis of symmetry is 2
2x^2-8x+8
2(x^2-4x)+8
2(x-2)^2-2(4)+8
2(x-2)^2-8+8
2(x-2)^2
^ on a graph would be at x=2
2x^2-8x+8
2(x^2-4x)+8
2(x-2)^2-2(4)+8
2(x-2)^2-8+8
2(x-2)^2
^ on a graph would be at x=2
Answer: 2 is the axis of symmetry for the given function.
Step-by-step explanation:
Given function [tex]f(x) = 2x^2-8x + 8[/tex] -------(1)
Since, the axis of symmetry is a line which divides the parabola into two equal halves that are the reflection of each other.
And, a quadratic function represents a parabola.
If a parabola is in the form of [tex]ax^2+bx+c[/tex],
Then, axis of symmetry, [tex]x=-\frac{b}{2a}[/tex]
Thus, axis of symmetry for the parabola represented by equation (1)
[tex]x=-\frac{-8}{2\times 2}=2[/tex]
⇒x=2
