Answer :
the new volume is 8.95 L
you can use the V1P1/T1=V2P2/T2
you know the pressures are the same
so the ratio of volume divided by temperature should be the same
so
4.5L/287K(kelvins you add 273 to celsius)=xL(unknown volume)/571K(the new temp)
this will give you the new volume!
you can use the V1P1/T1=V2P2/T2
you know the pressures are the same
so the ratio of volume divided by temperature should be the same
so
4.5L/287K(kelvins you add 273 to celsius)=xL(unknown volume)/571K(the new temp)
this will give you the new volume!