Answer :
The surface area of a right cylinder equals [tex]2 \pi rh+2 \pi r^2[/tex]
As you can see in the attached picture, the surface area consists of two equal circles (bottom and top one) and area that would look like a rectangle, if "unraveled".
The formulae for the surface area of the circle is [tex] \pi r^{2} [/tex]. You have to multiply it by two and add to the area of the "rectangle", which equals [tex]2 \pi rh[/tex] where [tex]2 \pi r[/tex] is the circumference of the circle and [tex]h[/tex] is the height of the cylinder.
As you can see in the attached picture, the surface area consists of two equal circles (bottom and top one) and area that would look like a rectangle, if "unraveled".
The formulae for the surface area of the circle is [tex] \pi r^{2} [/tex]. You have to multiply it by two and add to the area of the "rectangle", which equals [tex]2 \pi rh[/tex] where [tex]2 \pi r[/tex] is the circumference of the circle and [tex]h[/tex] is the height of the cylinder.
