Answer :

[tex]\Delta ABC\sim\Delta DAC\\\\then\\\\\frac{|AC|}{|BC|}=\frac{|CD|}{|AC|}\\\\|AC|^2=|BC|\cdot|CD|\\\\|AC|^2=4\cdot27\\\\|AC|=\sqrt{4\cdot27}\\\\|AC|=\sqrt4\cdot\sqrt{27}\\\\|AC|=2\cdot\sqrt{9\cdot3}\\\\|AC|=2\sqrt9\cdot\sqrt3\\\\|AC|=2\cdot3\sqrt3\\\\|AC|=6\sqrt3[/tex]

31 is the answer I think..

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