Answer :
Answer : 787.4 g
Explanation : With the given information; the volume of the block will be equal to = 5 cm X 10 cm X 2 cm = 100 [tex] cm^{3} [/tex].
Therefore, the volume will be 100 [tex] cm^{3} [/tex].
but density of iron is found to be [tex] 7.874 g/cm^{3} [/tex]
So, now calculating for mass; on the basis of the density formula;
which is density = mass/volume; so, mass = density X volume;
Therefore, mass will be 7.874 g X 100 = 787.4 g
mass of the iron block = 787.4 g
Explanation:
Given that,
The dimensions of the block of iron is 2 cm, 10 cm and 5 cm
To find,
The mass of the block.
Solution,
We know that, the density of iron is, d = 7.874 g/cm³
Density, [tex]d=\dfrac{m}{V}[/tex]
Where
m is mass and V is volume
Solving for m,
[tex]m=d\times V[/tex]
The block is in the form of a cuboid, [tex]V=lbh[/tex]
So,
[tex]m=d\times l\times b\times h\\\\m=7.874 \times 2\times 10\times 5\\\\m=787.4\ g[/tex]
Answer,
The mass of the block of iron is [tex]787.4\ g[/tex].
Reference,
https://brainly.com/question/5189059
