Answer :
[tex]J \rightarrow Jane\\
B \rightarrow Bill\\
T \rightarrow Tricia\\
S \rightarrow Steve\\\\
J+B+T+S = 135\\\\
(10 + (17 + (21 + S) ) )+(17+(21+S))+(21+S)+S=135\\\\
10 + 17 + 21 + S+17+21+S+21+S+S=135\\\\
4S+107=135\\\\
4S=135-107\\\\
S=\dfrac{28}{4}\\
\boxed{S=7}\\\\\
T=21+S\\
T=21+7\\
\boxed{T=28}\\\\
B=17+T\\
B=17+28\\
\boxed{B=45}\\\\
J=10+B\\
J=10+45\\
\boxed{J=55}[/tex]
[tex]55+45+28+7=135\\\\ \boxed{135=135}[/tex]
[tex]55+45+28+7=135\\\\ \boxed{135=135}[/tex]
Jane has $55, Bill has $45, Tricia has $28, and Steve has $7.
Given that
Jane has $10 more than Bill, Bill has $17 more than Tricia, and Tricia has $21 more than Steve.
If the total amount of all their money is $135.
We have to determine
How much money does each have?
According to the question
Let the amount Steve be x,
The total amount Jane has is (10 +17+21+x)
The total amount Bill has is (17+21+x)
The total amount Tricia has is (21+x)
Then,
The total amount of all money = Jane money + Bill money + Tricia money + Steve money
[tex]\rm 135 =( 10+17+21+x)+ (17+21+x) + (21+x)+x\\\\135 = 48+x + 38+x+21+x+x\\\\135 = 4x+ 107\\\\4x = 135-107\\\\4x = 28\\\\ x = \dfrac{28}{4}\\\\ x= 7[/tex]
The Steve has $7.
Therefore,
The total money Jane has = (10 +17+21+x) = 48 + 7 = $55
The total money Bill has = (17+21+x) = 38 +7 = $45
The total money Tricia has = (21+x) = 21 +7 = $28
Hence, Jane has $55, Bill has $45, Tricia has $28, and Steve has $7.
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https://brainly.com/question/14454996
