Answer :
You have 43 marbles in total.
Probability of picking red first:
P(red) = [tex] \frac{8}{43} [/tex]
Probability of picking blue:
P(blue) = [tex] \frac{12}{43} [/tex]
Note that the denominator is still 43 because the marble is replaced.
An important part of the question is that you're picking red, then blue. So you only care about the situations where red is picked first.
Total probability is:
P(red, then blue) = [tex] \frac{8}{43} [/tex] * [tex] \frac{12}{43} [/tex] = [tex] \frac{96}{1849} [/tex] ≈ 0.052
Probability of picking red first:
P(red) = [tex] \frac{8}{43} [/tex]
Probability of picking blue:
P(blue) = [tex] \frac{12}{43} [/tex]
Note that the denominator is still 43 because the marble is replaced.
An important part of the question is that you're picking red, then blue. So you only care about the situations where red is picked first.
Total probability is:
P(red, then blue) = [tex] \frac{8}{43} [/tex] * [tex] \frac{12}{43} [/tex] = [tex] \frac{96}{1849} [/tex] ≈ 0.052
Answer:
96/1849
Step-by-step explanation:
You have 43 marbles in total.
Probability of picking red first:
P(red) =
Probability of picking blue:
P(blue) =
Note that the denominator is still 43 because the marble is replaced.
An important part of the question is that you're picking red, then blue. So you only care about the situations where red is picked first.
Total probability is:
P(red, then blue) = * = ≈ 0.052
