Answer :
4x-2y=7 (1)
-3x+3y=10 (2)
3y= 3x+10
y= x+10/3 (3)
sub (3) into (1)
4x-2(x+10/3)=7
4x-2x-20/3=7
2x-20/3=7
+20/3 +20/3
2x= 41/3
x= (41/3) / 2
x= 41/6
sub x= 41/6 into (3)
y= 41/6+10/3
= 61/6
Therefore the point of intersection is (41/6, 61/6)
-3x+3y=10 (2)
3y= 3x+10
y= x+10/3 (3)
sub (3) into (1)
4x-2(x+10/3)=7
4x-2x-20/3=7
2x-20/3=7
+20/3 +20/3
2x= 41/3
x= (41/3) / 2
x= 41/6
sub x= 41/6 into (3)
y= 41/6+10/3
= 61/6
Therefore the point of intersection is (41/6, 61/6)
4x - 2y = 7 ⇒ -12x + 6y = -21
-3x + 3y = 10 ⇒ -12x + 12y = 40
-6y = -61
-6 -6
y = 10¹/₆
4x - 2(10¹/₆) = 7
4x - 8¹/₃ = 7
+ 8¹/₃ + 8¹/₃
4x = 15¹/₃
4 4
x = 3⁵/₆
(x, y) = (3⁵/₆, 10¹/₆)
-3x + 3y = 10 ⇒ -12x + 12y = 40
-6y = -61
-6 -6
y = 10¹/₆
4x - 2(10¹/₆) = 7
4x - 8¹/₃ = 7
+ 8¹/₃ + 8¹/₃
4x = 15¹/₃
4 4
x = 3⁵/₆
(x, y) = (3⁵/₆, 10¹/₆)
